Shortest Path Java Program
Java Program In Shortest Path Source Code
See The Code And Copy
To find the shortest path using Breadth First Search
code
import java.io.*;
import java.util.*;
class shortpath
{
public static int x1,x2,y1,y2,n,m;
public static int a[][]=new int[10][10],parent[][]=new
int[10][10],dist[][]=new int[10][10],i,j;
public static void main(String s[]) throws IOException
{
int x,y,num;
LinkedList l=new LinkedList();
LinkedList path=new LinkedList();
BufferedReader br=new BufferedReader(new
InputStreamReader(System.in));
System.out.println("Enter the value for n & m 1st matrix");
BufferedReader bf=new BufferedReader(new
InputStreamReader(System.in));
n=Integer.parseInt(bf.readLine());
m=Integer.parseInt(bf.readLine());
System.out.println("Enter the elements for 1st matrix(0 or 1)");
for(i=0;i
for(j=0;j
{
a[i][j]=Integer.parseInt(bf.readLine());
parent[i][j]=-1;
dist[i][j]=n*m;
}
System.out.println("Enter the position of source(x,y)");
x1=Integer.parseInt(bf.readLine());
y1=Integer.parseInt(bf.readLine());
System.out.println("Enter the position of Destination(x,y)");
x2=Integer.parseInt(bf.readLine());
y2=Integer.parseInt(bf.readLine());
l.add(getnum(x1,y1));
dist[x1][y1]=0;
while(l.size()!=0)
{
num=Integer.parseInt(l.removeLast().toString());
x=num/m;
y=num%m;
if(x>0&&a[x-1][y]!=1&&(dist[x-1][y]>(dist[x][y])+1))
{
l.add(getnum(x-1,y));
dist[x-1][y]=dist[x][y]+1;
parent[x-1][y]=num;
}
if(y>0&&a[x][y-1]!=1&&(dist[x][y-1]>(dist[x][y])+1))
{
l.add(getnum(x,y-1));
dist[x][y-1]=dist[x][y]+1;
parent[x][y-1]=num;
}
if(x(dist[x][y])+1))
{
l.add(getnum(x+1,y));
dist[x+1][y]=dist[x][y]+1;
parent[x+1][y]=num;
}
if(y(dist[x][y])+1))
{
l.add(getnum(x,y+1));
dist[x][y+1]=dist[x][y]+1;
parent[x][y+1]=num;
}
}
path.add("("+x2+","+y2+")");
x=x2;y=y2;
do{
num=parent[x][y];
x=num/m;
y=num%m;
path.add("("+x+","+y+")");
}while(!(x==x1&&y==y1));
while(path.size()!=0)
System.out.println(path.removeLast());
}
public static Integer getnum(int x,int y)
{
return new Integer(x*m+y);
}
}
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